Applied Test Series

Question

The packet is sent from source to router with the link having the maximum transmission unit (MTU) as 480 bytes, the header is of size 20 bytes. The intermediate fragment size is X and the last fragment size is Y when the packet size is of 2000 bytes including the header. Calculate the value of X+Y in bytes?

 

Answer 1

1880 bytes data + 20 bytes header

Total fragments = 1980 / 460= 5 fragments

Intermediate fragment size = 456 + 20 = 476

Last fragment size=  156 + 20 = 176 bytes.

X +Y = 652