Answer given as (C). Can't understand why ??

Question

Answer 1

We can reduce this to

$$L = \{0^n1^n0^m \mid n\geq 0, m \leq n\}.$$

We cannot make a PDA for this as we need to do 2 indefinite counts. But we can do this with an LBA and so $L$ is CSL. Answer should be B choice.