SWP Window size1.1

Question

Consider a link of length 1000 km with 10⁹ bps rate connecting a sender and receiver. Assume a fixed packet length of 2500 bytes and sender always has packets to send. Packets are never lost or corrupted in the connection. The necessary window size to achieve 90% utilization for a sliding window protocol is _________ (Assume signal propagation is 2 μsec per km [Approximately])

Answer 1

let window size=w

TT=2500*8/(10^9)=20μsec

PD=2*1000=2000μsec

efficiency=w*TT/(TT+2PT)

0.9=w*(1/201)

w=201*0.9=180.9=181