GO Classes Test Series 2024 | Programming | Test 1 | Question: 25

Answer 1

a = 0

b = a– –  ? a++ : a ? a++ : a– –  $\equiv$  b = a– –  ? a++ : (a ? a++ : a– –), ternary operator is Right to Left associative.

It is of the form expr1 ? expr2 : expr3. Here, expr1 = a– –, expr1 returns 0 (False) and makes a = –1. Thus, we execute expr3. Here, expr3 = a ? a++ : a– –, a is –1 (True), so it executes a++, which returns –1 and makes a = 0.

Therefore, b = –1.

Answer :- B

 

Comments

Here, precedence is helping us to put proper parenthesis, precedence doesn't define order of execution.

Precedence and associativity are independent from order of evaluation.

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shishir__roy

Yes , this is exactly what I was asking for. Thanks!

the order of execution will depend on that particular operator and how actually the compiler executes it.

is this correct now?

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Yes.