GO Classes Test Series 2024 | Programming | Test 3 | Question: 15

Answer 1

Given 32b number 0x 12345678 is stored at location 1000 in little endian format.

At 1000, 0x 78 is stored (not 87).

At 1001, 0x 56 is stored.

At 1002, 0x 34 is stored.

At 1003, 0x 12 is stored.

At 1002, 0x 34 is stored, which is equivalent to 3 * 16 + 4 = 52 in decimal.

Answer :- 52

Comments

Why is is 78 and not 87? Can you please explain this part?
Thanks.

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The endian system dictates whether we store MSB to LSB or LSB to MSB starting at some memory location.

$0x78$ is $1$ whole Byte, we do not alter the nibbles of a Byte, we store them as they are.