UGC NET CSE | October 2022 | Part 1 | Question: 55

Question

The representation of $4$ bit code $1101$ into $7$ bit, even parity Hamming code is

• A. $(1010101)$
• B. $(1111001)$
• C. $(1011101)$
• D. $(1110000)$

Answer 1

Suppose bits are P1 P2 B3 P4 B5 B6 B7

P1 is checked against P1, B3, B5 B7

P2 is checked against P2 B3 B6 B7

P4 is checked against P4 B5 B6 B7

So, the answer is 1010101. That is option A