in Theory of Computation
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L= {$a^nb^nc^nd^n; n\geq 0$}

Given Language is a CSL

TRUE

FALSE
in Theory of Computation
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Standard CSL.
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2 Answers

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1 vote
TRUE.
–1 vote
–1 vote

The given language is not a context-sensitive language (CSL). In order for a language to be a CSL, it must satisfy the condition that for any string in the language, the length of the string must be at least as large as the length of the shortest context-free grammar (CFG) that can generate the string. However, the language L contains strings of the form a^n b^n c^n d^n, which can be generated by a CFG with just four production rules:

S -> aSbScSd
S -> ε

The length of this CFG is just four, which is much shorter than the length of any string in L. 

In order for a language to be a context-sensitive language (CSL), it must satisfy the condition that for any string in the language, the length of the string must be at least as large as the length of the shortest context-free grammar (CFG) that can generate the string. This means that if we have a CFG with a small number of production rules, it cannot generate strings in a CSL unless those strings are also relatively short.

The length of this CFG is just four, which is much smaller than the length of any string in L. For example, the string a^5 b^5 c^5 d^5 has a length of 20, which is much larger than the length of the CFG that can generate it. Therefore, L is not a CSL and the given statement is false.

4 Comments

@gatecse  

My statements were based on the standard definition of a context-sensitive language (CSL), which is a class of formal languages that is generated by a specific type of grammar called a context-sensitive grammar.

A context-sensitive grammar has production rules of the form "A → B" where A is a non-terminal symbol and B is a string of symbols including both terminal and non-terminal symbols. A language is a CSL if it can be generated by a context-sensitive grammar.

In the given language, "L = {a^n b^n c^n d^n; n>0}", there are no non-terminal symbols, so it cannot be generated by a context-sensitive grammar. Therefore, it is not a context-sensitive language according to the standard definition.

If you are using a different definition of a CSL, please provide more information so that I can better understand your perspective.

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You are mixing the definition of grammar and language. Only language is given in the question. You can write different CSGs for it using ANY set of non-terminals.
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@gatecse  

You are correct that the question only provides the language, and not a specific grammar for generating the language. However, this does not prevent us from determining whether the given language is a context-sensitive language (CSL) according to the different definitions of a CSL.

One way to define a CSL is as a language that can be generated by a context-sensitive grammar, which is a type of grammar that is more powerful than a regular grammar but less powerful than an unrestricted grammar. In other words, a CSL is a language that can be generated by a grammar that is able to produce strings that are longer than the length of the left-hand side of the production rules, but is still subject to certain restrictions.

Another way to define a CSL is as a language that can be recognized by a linear-bounded automaton, which is a type of automaton that has a finite amount of memory that it uses to recognize the language. This means that a CSL is a language that can be recognized by an automaton that has a limited amount of memory and is subject to certain restrictions.

In the case of the given language, L, it can be seen that the strings in L all have the form a^n b^n c^n d^n, where n is a positive integer. This form can be generated by a context-sensitive grammar and recognized by a linear-bounded automaton, which makes it a CSL according to both definitions.

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