Fragmentation in Networking

Question

Suppose a 22-byte packet is to be transmitted through a network of MTU = 3byte. The elementary fragment size is 1 byte. Show the segment numbering of the above packet. Packet number is 127.

Answer 1

If a packet is 22 bytes and the MTU (maximum transmission unit) is 3 bytes, the packet will need to be split into multiple segments in order to be transmitted through the network. If the elementary fragment size is 1 byte, each segment will contain 1 byte of the original packet.

To determine the segment numbering for the packet, we first need to know the total number of segments that will be generated from the packet. We can determine this by dividing the size of the packet by the MTU: 22 bytes / 3 bytes/segment = 7.33 segments. Since each segment contains 1 byte of the original packet, we know that 7 segments will be needed to transmit the entire packet.

The numbering of the segments will depend on the packet number, which in this case is 127. The first segment will be numbered 127.1, the second segment will be numbered 127.2, and so on. The last segment will be numbered 127.7.

In summary, the segment numbering for the 22-byte packet with packet number 127 and an MTU of 3 bytes will be:

127.1 127.2 127.3 127.4 127.5 127.6 127.7