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GO 2023 Topic Wise Free Test 2 | First Order Logic | Question: 1

in Mathematical Logic
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In first-order logic, how would you express that "something likes something"?
  1. $\exists x \exists y \operatorname{Likes}(x, y)$
  2. $\exists x \forall y \operatorname{Likes}(x, \mathrm{y})$
  3. $\forall x \exists y \text{Likes}(x, y)$
  4. $\forall x \forall y \operatorname{Likes}(x, \mathrm{y})$
in Mathematical Logic
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1 Answer

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In English:
  1. something likes something,
  2. something likes everything,
  3. everything likes something,
  4. everything likes everything.
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