in Quantitative Aptitude edited by
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5 votes
5 votes

If $\log_{x}{(\frac{5}{7})}=\frac{-1}{3},$ then the value of $x$ is

  1. $343/125$
  2. $25/343$
  3. $-25/49$
  4. $-49/25$  
in Quantitative Aptitude edited by
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@lakshman can you tell the rule applying here
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2 Answers

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6 votes
Best answer
$\log_{x}{(\frac{5}{7})}=\frac{-1}{3} \implies x^{-\frac{1}{3}} = \frac{5}{7}$

$\implies x^{\frac{1}{3}} = \frac{7}{5}$

$\implies x = \left[{\frac{7}{5}}\right]^3 = \frac{343}{125}.$

Correct Option: A.
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4 votes
4 votes
I think the question given is log of 5/7 to base x = -1/3

then , x ^ (-1/3) = 5/7

implies, 1 / (x ^ (1/3) ) = 5/7

so x ^ (1/3) = 7/5

and x= (7/5) ^ 3

= 343/125

Option A is answer
Answer:

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