Cube is built using $64$ cubic blocks of side one unit. It means it is a $4\times 4\times 4$ Cube.
Surface area of each face $ = 4\times 4$ sq. units
And number of faces in a cube $= 6$, Thus total surface area $ = 6\times 4\times 4 = 96$ sq. units.
A cube contains $8$ corner pieces (containing $3$ visible sides), and if these are removed then inner ones are visible, So, When a corner piece is removed $3$ new faces of $1$ sq. unit are visible and thus removal doesn't change surface area.
Hence, Option $(D)$ is correct.