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A merchant can buy goods at the rate of Rs. $20$ per good. The particular good is part of an overall collection and the value is linked to the number of items that are already on the market. So, the merchant sells the first good for Rs. $2,$ second one for Rs. $4,$ third for Rs. $6, \ldots$ and so on. If he wants to make an overall profit of at least $40 \%$, what is the minimum number of goods he should sell?

  1. $24$
  2. $18$
  3. $27$
  4. $32$
in Quantitative Aptitude edited by
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2 Answers

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4 votes

Answer: C

Assume merchant buy $x$ number of products

Cost prize of $x$ items = $20x$

Selling prize of $x$ items = $\frac{x}{2}(2*2 + (x-1)*2) \implies \frac{x}{2}(4+2x-2) \implies x(x+1)$

Profit percentage = $40 \%$

$\frac{x(x+1) – 20x}{20x} = 0.4 \implies x-19 = 8 \implies x = 27$

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2 votes
2 votes
Let us assume he buys n goods.

Total CP = 20n

Total SP = 2 + 4 + 6 + 8 ….n terms

Total SP should be at least 40% more than total CP

2 + 4 + 6 + 8 ….n terms ≥ 1.4 * 20 n

2 (1 + 2 + 3 + ….n terms) ≥ 28n

n(n + 1) ≥ 28n

n2 + n ≥ 28n

n2 - 27n ≥ 0

n ≥ 27
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