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TCP connection termination using three-way handshaking is shown below.


Consider the following statements about this termination:

  1. Between $\text{B}$ and $\text{C},$ both-way communication is possible.
  2. Between $\text{B}$ and $\text{C, T}$ can still send data if $\text{T}$ wants but $\text{S}$ can't.
  3. $\text{X's}$ value is $4000.$
  4. $\text{Y's}$ value is $9500.$

Which of the above statements is/are true?

  1. II only
  2. I, III, and IV only
  3. I and II only
  4. II, III, and IV only
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1 Answer

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Between $\text{B}$ and $\text{C, S}$ is half close and at the label $\text{D, X}=4001, \text{Y}=9501$.

2 Comments

@GO Classes

I think statement III is correct as only Acknowledgment does not consume any sequence number.
So sequence number will remain same as 4000.

Hence, X=4000

So, II and III are correct.

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1

Please check the above @GO Classes. Since only ack the sequence number could remain the same.

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