in Quantitative Aptitude edited by
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If a prime number on division by $4$ gives a remainder of $1,$ then that number can be expressed as

  1. sum of squares of two natural numbers
  2. sum of cubes of two natural numbers
  3. sum of square roots of two natural numbers
  4. sum of cube roots of two natural numbers
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3 Answers

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Best answer

Theorem$:$ If $p$ is a prime number which has remainder $1$ when divided by $4,$ then $p$ can be written as a sum of two squares.

(Reference: http://math.arizona.edu/~wmc/Courses/323044/Lecture4.pdf )

Example$:$

  • $5 = 1 + 4$
  • $13 = 9 + 4$
  • $17 = 16 + 1$
  • $29 = 25 + 4$
  • $37 = 36 + 1$
  • $41 = 25 + 16$
  • $53 = 49 + 4$
  • $61 = 36 + 25$
  • $73 = 64 + 9$
  • and so on.


So, option $(A)$ is correct.

Take option $(B)$ sum of cubes of two natural numbers.

Counter example$:\ 5$ cannot represent as cubes of two natural numbers $(1^{3}=1,2^{3}=8\implies 1 + 8 = 9\neq 5).$

So, option $(B)$ is not correct.

Take option $(C)$ sum of square roots of two natural numbers

Let $p = 4n + 1, n \geq 0$ and $p$ is prime. 

The smallest such $p$ is $5.$

So, any $p$ can be written as $ p = p_1 + p_2$ where $p_1$ and $p_2$ are natural numbers. Now, existence of $p_1^2$ and $p_2^2$ makes option C correct.

For option D, instead of $p_1^2$ and $p_2^2$ in above explanation we just need to change to $p_1^3$ and $p_2^3.$

Correct options $: \ (A), \ (C), \ (D).$

It is better to pick option A here, because Options C and D seem to be given by mistake. Nowadays at least in GATE this will cause Marks to All during debate.

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3 Comments

OP bhai ! :) I was confused in this
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@Lakshman Patel RJIT  we can also say that options C and D are trivially true. right??

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@abir_banerjee These seem trivial, but we always need to be proven.

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we can express them as sum of square roots of 2 natural numbers definitely.

eg: 17,29,41 etc..

17 = 9 +8 =Sq root of 81 + Sq root of 64

like that we can express.

Option C is answer i guess
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x mod 4=1 ..13 can be one such number and it is also prime ..can be expressed as ..2 2+32=>13..

so option A seems to be the correct one 

can be applied on 17-> 42+12... and so on..

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4 Comments

now I have checked with so many numbers and I think C and D are also true ..but the answer given is A..this should have been MTA..
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Trying proof for A?
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Sir, but even if we prove A, we cant disprove C or D :P
take any number of the form
X=4q+1
We can write X as sum of any two possible natural numbers,say 
X = Y + Z

Now Y is a square root of natural number Yand Z is a square root of natural number Z2

Similarly for Cube roots.
So i think the question has something wrong in it.
 

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