GATE2013 EE: GA-2

Question

In the summer of $2012$, in New Delhi, the mean temperature of Monday to Wednesday was $41°C$ and of Tuesday to Thursday was $43°C$. If the temperature on Thursday was $15\%$ higher than that of Monday, then the temperature in $°C$ on Thursday was

• A. $40$
• B. $43$
• C. $46$
• D. $49$

Comments

It should be 15% not 15

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@Arjun sir please explain this ques

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Someone please update the question!

Answer 1

Let the temperatures on Monday, Tuesday, Wednesday, and Thursday be $x^∘,  y^∘,  z^∘,$ and $w^∘C$ respectively.

Given that,

• $x+y+z = 3 \times 41$
• $y+z+w = 3\times 43$

Thursday temperature is $15\%$ higher than Monday temperature. So, 

• $w = 1.15x$

After solving above equations, we get $w=46$

Therefore, correct answer is (C).

Answer 2

$\dfrac{M+T+W}{3}=41$

$\dfrac{T+W+Th}{3}=43$

$M+T+W=123\ \ ....(1)$

$T+W+Th=129\ \ ....(2)$

$Subtract\ (1)\ from\ (2) $

$Th-M=6\ \ ....(3)$

If the temperature on Thursday was 15% higher than that of Monday.

$Th=\dfrac{115}{100}M$

$Substitute\ the\ value\ of\ 'Th'\ in\ (3)$

$\dfrac{115}{100}M-M=6$

$15M=600$

$M=40$

$\therefore Th=46$

 

Comments

Thanks Sir :)

Answer 3

MON+TUES+WED=41*3=123-----------(1)

TUE+WED +THURS=43*3=129--------(2)

Substracting (1) from (2) we get THURS - MON= 6

Also it is said that Temperature of THURS is 15 % higher than Monday.

hence 15%=6

hENCE 100%=6/15*100= 40 WHICH IS THE TEMPERATURE of Monday.

The temperature of Thursday is 46  and the option  C is correct.