The sentence "All students are not equal" can be translated into First-Order Logic (FOL) in different ways, but only one option accurately reflects the meaning. Let's analyze each option:
A. βπ₯ βπ¦[π π‘π’ππππ‘(π₯) β§ π π‘π’ππππ‘(π¦)] β Β¬πΈππ’ππ(π₯, π¦)
- This translates to "For every student x, there exists another student y such that x is not equal to y."
- This option is incorrect because it doesn't say that all students are different, just that for any student, there exists another who is different.
B. βπ₯ βπ¦[π π‘π’ππππ‘(π₯) β§ π π‘π’ππππ‘(π¦)] β Β¬πΈππ’ππ(π₯, π¦)
- This translates to "For every student x and every student y, x is not equal to y."
- This option is too strong because it implies that no student can be equal to themselves, which is not the intended meaning of the original sentence.
C. βπ₯ βπ¦[π π‘π’απππ‘(π₯) β§ π π‘π’ππππ‘(π¦) β§ Β¬πΈππ’ππ(π₯, π¦)]
- This translates to "For every student x, there exists another student y such that x is student and y is student and they are not equal."
- This option is correct. It captures the essence of the original sentence by stating that for any student, there exists another student who is different.
**D. βπ₯ βπ¦[π π‘π’ππππ‘(π₯) β§ π π‘π’ππππ‘(π¦) β§ Β¬πΈππ’ππ(π₯, π¦)] **
- This is the same as option B and is therefore too strong and incorrect.
Therefore, the First-Order Logic sentence that closest matches the original sentence "All students are not equal" is C. βπ₯ βπ¦[π π‘π’ππαπ‘(π₯) β§ π π‘π’ππππ‘(π¦) β§ Β¬πΈππ’ππ(π₯, π¦)].