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UGC NET CSE | June 2008 | Part 2 | Question: 39

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With $64$ bit virtual addresses, a $4 \mathrm{~KB}$ page and $256 \mathrm{MB}$ of RAM, an inverted page table requires :

  1. $8192$ entries.
  2. $16384$ entries.
  3. $32768$ entries.
  4. $65536$ entries.

     

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