in Others edited by
98 views
0 votes
0 votes

For two languages $\text{A, B}$ over the alphabet $\Sigma$, let the perfect shuffle of $\text{A}$ and $\text{B}$ be the language

\begin{Bmatrix}
w=a_1 b_1 a_2 b_2 \cdots a_k b_k \text{where} a_1 a_2 \cdots a_k \in \text{A} and b_1 b_2 \cdots b_k \in B.& \\ \text{and} k \in\mathbb{N}
 & 
\end{Bmatrix}

Consider the following statements.

  1. If $\text{A}$ and $\text{B}$ are regular, then perfect shuffle of $\text{A}$ and $\text{B}$ is regular.
  2. If $\text{A}$ and $\text{B}$ are regular, then perfect shuffle of $\text{A}$ and $\text{B}$ is context-free.
  3. If $\text{A}$ and $\text{B}$ are decidable, then perfect shuffle of $\text{A}$ and $\text{B}$ is decidable.

Which of above statements is/are true?

  1. All of $\text{(i), (ii) and (iii)}$.
  2. Only $\text{(i) and (ii)}$.
  3. Only $\text{(ii)}$.
  4. Only $\text{(ii) and (iii)}$.
  5. None of $\text{(i), (ii), (iii)}$ is true.

     

in Others edited by
by
98 views

1 Answer

0 votes
0 votes

For 1 and 2 proofs are in pdfs

http://www.cs.nthu.edu.tw/~wkhon/assignments/assign1ans.pdf

http://im.ntu.edu.tw/~tsay/dokuwiki/lib/exe/fetch.php?media=courses:theory2014:theory2014mid_s.pdf

 

Answer:

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true