GO Classes Test Series 2024 | Mock GATE | Test 12 | Question: 36

Answer 1

(B) (C) FTTF.  (A) is false since $P(A \cup B)=P(A)+P(B)-P(A \cap B)=0.7$.

(B) is true since $P(A \cup C)=P(A)+P(C)-P(A \cap C)=1$.

(C) is false. In view of Option (B),  $C=A^c$ and thus $P(B)=P(B \cap A)+P(B \cap C)$. So, $P(B \cap C) = 0.2 .$

(D) Using (C) it follows that $P(B \cup C)=0.8$.

Comments

P(B ∩ C) should be 0.2 not 0.23. If it is 0.23 then P(B) will become 0.3+0.23=0.53 which is wrong

---

Answer will be only option B

---

Answer will be Option B only. In option C, $P(B \cap C) $ will be $0.2$, Not $0.23.$ Answer has been corrected now.

---

Sir also regenerate the result on go website. Since Marks not updated.