GO Classes Test Series 2024 | Mock GATE | Test 12 | Question: 26

Answer 1

Initially i = 6

now when entering into the loop first “—i” or pre-decrement of i at the initialization point  makes 6 to 5 and another “—i” which is at  the condition point makes 5 to 4

now when entered into the loop it will give 4 as output.

now after one iteration again one decrement that is post decrement which will make i = 4 to i =3

now again come to the checking point it will make i = 3 to i =2

now enter the loop and print 2

now after the second iteration post decrement will make i = 2 to i =1

and at the checking point as pre decrement is present it will first reduce the value to 0 and the checking condition fails and terminate the loop.

and the final output will be 42.

Comments

why i cannot be negative, after 0 can’t i decrement to -1 to -2 and goes till the lowest limit of integer range?

---

Because at checking condition it will become 0 and 0 means false so it will get terminated. value other than zero are true in programming