Host $\text{A}$ and $\text{B}$ are behind different NATs. $\text{A's}$ private IP address is $192.168.1.11,$ and $\text{B's}$ private IP is $10.1.1.12.$ The public IP of the NAT box connected to $\text{A}$ is $4.3.2.1$ and the public IP of the NAT box connected to $\text{B}$ is $2.2.2.2.$
When $\text{A}$ sends a packet to $\text{B},$ what should be the destination IP address in the packet leaving $\text{A}?$
- $4.3.2.1$
- $2.2.2.2$
- $10.1.1.12$
- $1.2.3.4$
