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Football teams $T_1$ and $T_2$ play two games against each other in the Premier League. It is assumed that the outcomes of the two games are independent of each other. The probabilities of $T_1$ winning, drawing and losing against $T_2$ are $\dfrac{1}{2}, \dfrac{1}{6}$ and $\dfrac{1}{3}$ respectively. Each team gets $3$ points for a win, $1$ point for a draw, and $0$ points for a loss in a game. Let $X$ and $Y$ denote the total points scored in these two games by team $T_1$ and $T_2$, respectively.

What will be the value of $P(X=Y)?$

  1. $1 / 3$
  2. $13 / 36$
  3. $1 / 36$
  4. $1 / 18$
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All India Mock Test 4 - Solutions Part 1

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There are $9$ possible outcomes. Write down all $9$ possible outcomes for $\text{T}_1$ and corresponding $X$ and $Y$.
$$
\begin{array}{c|c|c|c}
\hline \textbf{1st Match} & \textbf{2nd Match} & \textbf{X} & \textbf{Y} \\
\hline \mathrm{w} & \mathrm{w} & 6 & 0 \\
\mathrm{w} & \mathrm{d} & 4 & 1 \\
\mathrm{w} & \mathrm{l} & 3 & 3 \\
\mathrm{~d} & \mathrm{w} & 4 & 1 \\
\mathrm{~d} & \mathrm{~d} & 2 & 2 \\
\mathrm{~d} & \mathrm{l} & 1 & 4 \\
\mathrm{l} & \mathrm{w} & 3 & 3 \\
\mathrm{l} & \mathrm{d} & 1 & 4 \\
\mathrm{l} & \mathrm{l} & 0 & 6 \\
\hline
\end{array}
$$
From the above table, we have

$P(X=Y)=P(w l)+P(d d)+p(l w)= P(w) P(l)+P(d) P(d)+P(l) P(w)$

$ = 1 / 2 * 1 / 3+1 / 6 * 1 / 6+1 / 3 * 1 / 2=13 / 36$
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