I was getting $\dfrac{1}{8}$ as answer by the following logic.
I modeled the problem as the following graph,
Where the orange shaded region is all the possibilities and green region is the favorable possibilities $(x\ge y)$.
The areas was coming out to be
Area of orange region $= 2 \cdot 2 = 4$
Area of green region $= \dfrac{1}{2}\cdot 1 \cdot 1 = \dfrac{1}{2}$
Probability $ = \dfrac{\dfrac{1}{2}}{4} = \dfrac{1}{8} = 0.125$
I also had given the DA exam but not found this question or i just panicked during exam and not able to answer this question
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