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how to simplify this boolean function i tend to get confuse on this given problem F(a,b,c)=(AB+AC)'+A'B'C
in Digital Logic
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1 Answer

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Simply expanding it : 

(AB+AC)' = (AB)'(AC)' [Demorgan] 
= (A'+B')(A'+C')
= A' + A'C' + A'B' + B'C'
A'(1+B'+C') + B'C'
= A' + B'C' [Absorption]

Or you can go by the good old K-map
 
B'C'B'CBCBC'
A'1111
A1000

Filled for (AB+AC)' : 
 
B'C'B'CBCBC'
A'1111
A1000

Add for A'B'C : It is already included from previous min-term.
From the above K Map
 F = A' + B'C'