If we try to analyze the regular language, we get L1 = set of strings where number of a's is odd.
For all strings of length 'x' half of them will have odd number of a's i.e. x/2 (think why)
So, we can sum up half of total strings of all lengths (upto 4) in L1 = 1/2 + 2/2 + 4/2 + 8/2 + 16/2 = 15.
These all will be readily available in L2 since it is (a+b)*