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​​​​​​When six unbiased dice are rolled simultaneously, the probability of getting all distinct numbers $(i.e., 1, 2, 3, 4, 5, \text{and }   6)$ is

  1. $\frac{1}{324}$
  2. $\frac{5}{324}$
  3. $\frac{7}{324}$
  4. $\frac{11}{324}$
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Answer: $6!/6^6 = 5/324.$
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