Checking by Elimination:
X -> Y is Fallacy (False) if X = T and Y = F.
Let's try to make RHS of propositions a Fallacy, and put those values of X and Y in LHS to check if an option is tautology.
A) for X = F, Y = T we get RHS = F an LHS = T.
Overall, T -> F = F. Hence it is not tautology.
B) for X= F, Y = F we get F -> F = T. Tautology
C) for X= F, Y = F we get F -> F = T. Tautology
D) for X= F, Y = T we get F -> F = T. Tauotlogy
B, C, D are correct options.