in Mathematical Logic
127 views
1 vote
1 vote
a) ~p\/q        b) ~q=>~p

c) ~p=>~q    d) ~(p/\~q)

can someone provide the solution?
in Mathematical Logic
127 views

1 Answer

1 vote
1 vote

We have p -> q as a true proposition.

That means for p as true and q as false we can't have the truth value as True. Because T -> F is False. 

Now since we have p = True and q = False as a test condition to check all the options we can use proof by examples to evaluate the final answer.

Option a: not p or q : not (True) or False = False or False = False. 

Option b: not q -> not p : not(False) -> not(True) = True-> False = False

Option c: not p -> not q : not(True) -> not(False) = False-> True = True (This is the wrong option)

Option d: not (p and not q) : not(True and not(False)) = not(True and True) = not(True) = False

So out of the given options only option c cannot be determined. 

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true