This should be the DFA for the given language. Since not mentioned explicitly, have taken $\epsilon$ as a member too.
We can frame the equation by looking at the Automata
$\epsilon$ + (0 + 1)0$^*$ + (0 + 1)10$^*$
or you can simplify it to
$\epsilon$ + 00$^*$ + 10$^*$ + 010$^*$ + 110$^*$
$\epsilon$ + 0(0$^*$ + 10$^*$) + 1($\epsilon$ + 1)0$^*$