I think more appropriate question would be 'number of steps' rather than number of 'productions'
To derive $x$ terminals we need $x$ non terminals. The $x$ non terminals can be derived as -
$<non-terminal> \rightarrow <non-terminal> <non-terminal>$
in $x-1$ steps as in the above production type every non terminal consumes one symbol at LHS and produces two non-terminals at RHS in each step except the first step where LHS is starting symbol.
The $x$ terminals from $x$ non terminals can be derived using -
$<non-terminal> \rightarrow <terminal>$
in $x$ steps
Hence total steps are $2x - 1$