Prog / What is the output of the following program?

Question

#include<stdio.h>
int main()
{
    char c=125;
    c=c+10;
    printf("%d",c);
    return 0;
}

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(a) 135 (b) +INF (c) -121 (c) -8

Comments

In this by default its Signed char or Unsigned?

Answer 1

By default its signed so we can get -121 as result

since 125+10 initally 125+2 =127 when 127+1=-128(we move to -ve values) because for char the range is from -128 to +127

So 125+10=-121

if it is unsigned char then we get 125+10=135

Comments

range :  

signed char	1 byte	-128 to 127
Unsigned char	1 byte	0 to 255

ref : http://www.tutorialspoint.com/cprogramming/c_data_types.htm

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I'm sorry u r right I will edit answer