$n$-th derivative of $x^n$ is
Ans - D. n!
f(x) = xⁿ f'(x) = n x(n-1) f''(x) = n(n-1) x(n-2) f'''(x) = n(n-1)(n-2) x(n-3) fⁿ(x) = n! x(n-n) , and since n-n = 0, x0 =1, so fⁿ(x) = n!
Hence,Option(D)n! is the correct choice.
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