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$n$-th derivative of $x^n$ is

  1. $nx^{n-1}$
  2. $n^n.n!$
  3. $nx^n!$
  4. $n!$
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Ans - D. n!

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Best answer

 f(x) = xⁿ 

f'(x) = n x(n-1) 

f''(x) = n(n-1) x(n-2) 

f'''(x) = n(n-1)(n-2) x(n-3) 

fⁿ(x) = n! x(n-n) , and since n-n = 0, x0 =1, 

so fⁿ(x) = n! 

Hence,Option(D)n! is the correct choice.
 

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