UGC NET CSE | June 2014 | Part 3 | Question: 55

Question

Given an image of size $1024 \times 1024$ pixels in which intensity of each pixel is an $8$-bit quality. It requires _______ of storage space if the image is not compressed.

• A. One Terabyte
• B. One Megabyte
• C. $8$ Megabytes 
• D. $8$ Terabytes 

Answer 1

Each pixel needs to store 1 Byte( 8 bit)

Total 1024 x 1024 pixels

Total storage space = 1024 x 1024 x 1 = 2 ¹⁰ x 2 ¹⁰ x 1 = 2 ²⁰ = 1 MB

Answer B

Answer 2

Total memory requirements is 1024 * 1024 *8 bits. to convert it to byte we need to divide by 8 then to kb we need to divide by 1024 and then to mega byte again need to divide by 1024, resulting in 1 value. so the result is 1 Megabyte.