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consider the effect of using slow start on a line with 10msec RTT and no congestion.The recieve window size is 24 KB and the maximum segment size is 2 KB.how long does it take before the first full window can be sent?
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  • In 1st RTT, 1st transmission 1MSS (2KB)
  • In 2nd RTT,2nd transmission 2MSS (4KB)
  • In 3rd RTT,3rd transmission 4MSS (8KB)
  • In 4th RTT,4th transmission 8MSS (16KB)

In 5th RTT 16MSS (32KB) is not possible in slow start (exceeds 24KB limit). 

Time before the 5th RTT or full window of 24 KB = 4*RTT = 40ms

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