in Computer Networks recategorized by
2,783 views
2 votes
2 votes

Using p=3, q=13, d=7 and e=3 in the RSA algorithm, what is the value of ciphertext for a plain text 5?

  1. 13
  2. 21
  3. 26
  4. 33
in Computer Networks recategorized by
2.8k views

2 Answers

1 vote
1 vote
all options are incorrect and perhaps question too

everything (e,d,p,q,P) is given in question just need to verfiy from the ans but options are not verificable

C=P^e mod n

P=5 , e=3 ,n=pq=39

C=5^3mod39=>125mod39=8 not in option
0 votes
0 votes
Encryption: C=T^e (mod pq) =5^3(mod39) =26mod39 =26
by

1 comment

How 5*3 gives you 26?..

its 125mod39 so ans is 8 .no option is correct
0
0
Answer:

Related questions