GATE CSE 2000 | Question: 1.11

Question

The following C declarations:

struct node { 
    int i:
    float j;
 };
 struct node *s[10];

define s to be:

• A. An array, each element of which is a pointer to a structure of type node
• B. A structure of $2$ fields, each field being a pointer to an array of $10$ elements
• C. A structure of $3$ fields: an integer, a float, and an array of $10$ elements
• D. An array, each element of which is a structure of type node

Answer 1

Correct Option: A

$[]$ has greater precedence than $*$ in C. So, $s$ becomes an array of pointers.

Comments

1. C Right-Left Rule (Rick Ord's CSE 131 - UC San Diego) (ucsd.edu) - BRAHMASTRA rule to read complicated pointer statements

Answer 2

The reference id from *s[10] to the structure and not vice-versa, ruling out options B & C.
The main ambiguity lies among options A & D.
Declaration of the type : struct node s[10] == option D.
*s[10] is an array of 10 pointers, each of type struct node. Hence, option A is the correct answer.
The precedence among operators * & [] can also be another determining factor.
 

                                    

Answer 3

Option A

This is easily solvable by the spiral rule.

http://c-faq.com/decl/spiral.anderson.html

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Even complex declarations can be figured out using this.

Source: https://stackoverflow.com/questions/34548762/c-isnt-that-hard-void-f

Comments

Nice one

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Never came across with this! thanks :)

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This needs to be bumped more.

Answer 4

Ans: A An array, each element of which is a pointer to a structure of type node