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Can someone show insertion steps for this question? Also, how can the order be odd as it is equal to 2*d(minimum degree)...because when i try to split during insertion of 4, i get confusion how to split?

The following key values are inserted into a B+ - tree in which order of the internal nodes is 3, and that of the leaf nodes is 2, in the sequence given below. The order of internal nodes is the maximum number of tree pointers in each node, and the order of leaf nodes is the maximum number of data items that can be stored in it. The B+ - tree is initially empty

10, 3, 6, 8, 4, 2, 1

The maximum number of times leaf nodes would get split up as a result of these insertions is
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3 Comments

check this !

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but bro here order of leaf node is 2 so we can accomodate only 1 key ..how to accomodate 2 keys in leaf node.. i got 6 .
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when it is given leaf node order that means no of data block pointer and for internal node it is block pointer...
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