Let x2 = t, Limit value x = [ 1 , 4 ] => t = [ 1 , 16 ]
And 2x dx = dt
=> 2dx / x = dt / x2 = dt / t.
∫ (2 esinx^2 / x) dx
= ∫ (esin t ) / t dt
= ∫ F ' ( t) dt // d/dx [f(x)] = esinx / x , x > 0
= [F(t) ]116
= F(16 ) - F(1)
Ans - k= 16.
64.3k questions
77.9k answers
244k comments
80.0k users