Which one of the following is NOT equivalent to $p ↔ q$?
@Swami patil (¬p ∨ q) ∧ (¬q ∨ p)(Convert into SOP from)
=(p' + q)(q' + p)
=(p'q' + qp)
=(¬p ∧ ¬q ) ∨ (p ∧ q ) Option (d)
Sahiltam Use truth tables.
Fixed now
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