L1 is regular but L2 is DCFL. So 4th point incorrect.
DCFL with regular closed under intersection(DCFL $\cap$ Regular = DCFL), Union(DCFL $\cup$ Regular= DCFL), concatenation(DCFL .Regular = DCFL) , minus (Regular - DCFL = Regular $\cap$ DCFL' = Regular $\cap$ DCFL = DCFL) so all 1,2,3 are DCFL too.