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Let the search key field of a B+ tree is 4 Bytes , the disk block size is 199 Bytes , and the index pointer is 3 Bytes, then the order of B+ tree is _______
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n*3 + (n-1)4 <=199 , n<=29 , so order is 29
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4 Comments

sorry sir ,  it was typo i am saying it must be less than 29 every node need to sum additional information

am i not correct?
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it is a B + tree so read B+ tree property once.

and see my given answer.
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index pointer is tree pointer or node pointer. right?
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Answer:

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