Test by Bikram | Digital Logic | Test 2 | Question: 6

Question

When simplified with Boolean Algebra, $(x + y)(x + z)$ simplifies to:

• A. $x$
• B. $x + x(y + z)$
• C. $x(1 + yz)$
• D. $x + yz$

Comments

x+yz

---

explain please i am getting B

---

paste your solution, I think you are doing some error

Answer 1

Given that $(x+y)(x+z)$

$\implies x\cdot x + x\cdot z + y\cdot x + y\cdot z$

$\implies x + xz + xy + yz$

$\implies x(1+z+y) + yz$

$\implies x\cdot 1 + yz$     $[\because1+X = 1]$

$\implies x +yz$