Test by Bikram | General Aptitude | Test 2 | Question: 12

Question

A number $1$5 is divided into three parts which are in A.P. and the sum of their squares is $83$.

The highest part is:

• A. $3$
• B. $5$
• C. $6$
• D. $7$

Answer 1

Let the $3$ numbers be $x-y , x , x+y$

Then, $x-y +x + x+y =15$

$\implies 3x= 15, x = 5$

Now put this value into their squares. $(5-y)^2 + 25 +( 5+y)^2 = 83$ and we get $y^2 = 4 \implies y = \pm 2.$

Hence, numbers are $5, 7,3 .$

And highest part is $7$

Comments

how y+z=10???

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3 numbers 

x-y , x , x+y

then x-y +x + x+y =15 

3x= 5 

x=5  now put this value into their square . (5-y)² + 25 +( 5+y)² = 83 and get y value as 2 so small one is 5-2 =3

x+y = 5+2=7 ( second no)

hence numbers are 5, 7,3