OS-bounded waiting

Question

does B satisfy BW?

 

Comments

Boundation waiting is not satisfied P1 can go as many times as it wants without worrying about P2. While there should be a boundation of number of attempts.
Secondly there is no facility by which Process P2 can show its interest. and same can happen with P1 too

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@saurabh,i got it.

one process repeatedly access CS ,second process is delayed . when two processes also present bounded waiting may not be satisfied..

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now if i consider counting semaphore initialized to 1 instead of binary semaphore then bounded waiting will be satisfied. am i correct?