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3nf decomposition
Consider R(ABCDEF) with following fd AB->CDEF C->A D->B C->D E->F B->E Decompose it into 3NF
answered
in
Databases
Oct 19, 2015
868
views
28
votes
2
TIFR CSE 2011 | Part A | Question: 2
In how many ways can the letters of the word $\text{ABACUS}$ be rearranged such that the vowels always appear together? $\dfrac{(6+3)!}{2!}$ $\dfrac{6!}{2!}$ $\dfrac{3!3!}{2!}$ $\dfrac{4!3!}{2!}$ None of the above
answered
in
Combinatory
Oct 15, 2015
1.5k
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tifr2011
combinatory
counting
1
vote
3
dijkstra's algo
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in
Algorithms
Oct 13, 2015
692
views
graph-algorithms
shortest-path
8
votes
4
Find number of variables in optimized code
Consider following 3 address code t1 = t+e t2 = g+a t3 = t1*t2 t4 = t2+t2 t5 = t4+t3 The minimum number of temporary variables that can be used in equivalent 3-address code of above code is Approach: t = t+e, g = g+a, t = t*g, g = g+g,t = t+g. Hence 4 temporary variables are needed. Is this right?
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in
Compiler Design
Oct 12, 2015
2.4k
views
compiler-design
intermediate-code
three-address-code
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