Perimeter(window) $= 6$ m
$\implies 5a = 6$ m
$\implies a = \dfrac{6}{5}$ m
$\implies a = 1.2$ m
Area(window) $=$ Area(triangle) $+$ Area(square)
$\qquad = \dfrac{\sqrt{3}}{4}a^2 + a^2$
$\qquad = \dfrac{\sqrt{3}}{4}{(1.2)}^2 + {(1.2)}^2$
$\qquad = 2.06 \ \text{m}^2$
Correct Answer: $B$