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A logic circuit has three input bits: $x_0$, $x_1$, and $x_2$, where $x_0$ is the least significant bit and $x_2$ is the most significant bit. The output from the circuit is $1$ when its input is any of the $3-bit$ numbers $1$, $4$, $5$, or $6$; otherwise, it is $0$. Which of the following expressions represents the output from this circuit?

Here $\sim x$ means Inverse of $x$ .

  1. $\sim x_2 +\sim x_1 + \sim x_0$
  2. $\sim x_2x_0 + \sim x_2 +\sim x_1$
  3. $x_2+ \sim x_1x_0$
  4. $\sim x_1x_0+x_2 \sim x_0$
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3 Comments

option $D$ is misprinted!
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@Bikram

sir none of option is matching with ans.

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@Arjun Sir, Kindly correct the options of this question. Last option which is answer and it's wrong. I got confused in the exam.

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2 Answers

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Best answer

Ans D.)

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answer not match.
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@Bikram Sir, I am getting option c as the answer/ what am i doing wrong here?

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Check for wrong combination, like C OPTION is giving o/p 1 when giving $x_{2}x_{1}x_{0}$ as i/p 111(7).
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1 vote
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f(x2x1x0) = $\sum$ (1,4,5,6) = ~x1x0  +  x2~x0

Answer:

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