T(n) =2 T$(\frac{n}{4})$ - n2
f(n) is not positive -> Masters theorem cannot be applied..... but could be solved by tree and substitution method!
T (n) = 2T (n/2) + n/ log n
Another example ..that can't be solved by masters theorem because of non-polynomial difference between f(n) and
i dont know about my solution, please update if u found anything wrong
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