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#SlidingWindow
S Harika
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Computer Networks
Apr 9, 2017
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In an ethernet using sliding window protocol ,sender window size is 5 and receiver window size is 3.How many bits are required to store maximum sequence number??
S Harika
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Apr 9, 2017
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S Harika
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Min sequence bit required = log(Sender Window Size + Reciever Window Size ) = log (5 + 3) = 3 bits
correct me if i am wrong :D
aehkn
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Apr 9, 2017
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aehkn
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Nitesh Choudhary
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Jun 12, 2017
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Answer is 4 bit
Because receivers window size>1
So this is selective repeat arq
And in this protocol sws<=2^(m-1)
As well as rws<=2^(m-1)
5<=2^(m-1)
So m=4
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S Harika
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#SlidingWindow
The efficiency of a 16 Mbps ethernet is 3/4.Cable length is 100 km and frame size is 1000 bytes.If the network is using sliding window protocol,what is the window size?
S Harika
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Computer Networks
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