Test by Bikram | Mock GATE | Test 4 | Question: 63

Question

A glass contained a mixture of two different flavoured liquids, $j$ and $k$ in the ratio $4 : 1$.  When $10$ litres of the mixture was replaced with liquid $k$, the ratio became $2 : 3$.

The volume of liquid $j$ originally present in the jar, therefore, was ________ litres.

Comments

Let $j= 4x, k= x$

When $10$ litre is removed, $j$ become $4x- \frac{4}{5} * 10$ = $4x-8$

When $10$ litre is removed, $k$ become $x-\frac{1}{5}*10$ = $x-2$

$10$ litre of $k$ is added, $k$ become= $x-2+10= x+8$

Final ratio of $j$ and $k$ is $\frac{2}{3}$= $\frac{4x-8}{x+8}$=$\frac{2}{3}$

On solving $x= 4$, Initial amount of $j$ is $4x= 4*4 = 16$ litre

Answer 1

16 litres will be answer..

Answer 2

Ifany error please please mention